本文介紹了媒體播放器-搜索欄和時(shí)間標(biāo)簽沒有進(jìn)展的處理方法，對(duì)大家解決問題具有一定的參考價(jià)值，需要的朋友們下面隨著小編來一起學(xué)習(xí)吧！
問題描述
IDK為什么，但在僅從此video
復(fù)制整個(gè)mainactity.Java文件之后
IDK為什么我的搜索欄和時(shí)間表沒有顯示任何進(jìn)展
有一個(gè)例外，我有兩個(gè)音頻文件，但視頻節(jié)目只有一個(gè)，所以我已經(jīng)將所有方法以及onClick和一個(gè)與之不同的對(duì)話框翻了一番
MainActivity.Java
public class MainActivity extends AppCompatActivity {
MediaPlayer player1;
MediaPlayer player2;
SeekBar seekBar1;
SeekBar seekBar2;
TextView elapsedTimeLable1;
TextView elapsedTimeLable2;
TextView remainingTimeLable1;
TextView remainingTimeLable2;
ImageView play1;
ImageView play2;
int totalTime1;
int totalTime2;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
// PlayButton * The ButtonClick is in the last if you want to jump directly there *
play1 = findViewById(R.id.playbtn1);
play2 = findViewById(R.id.playbtn2);
// TimeLables
elapsedTimeLable1 = findViewById(R.id.cTime1);
elapsedTimeLable2 = findViewById(R.id.cTime2);
remainingTimeLable1 = findViewById(R.id.tTime1);
remainingTimeLable2 = findViewById(R.id.tTime2);
// MediaPlayer
player1 = MediaPlayer.create(this, R.raw.dog_howl);
player1.setLooping(true);
player1.seekTo(0);
totalTime1 = player1.getDuration();
player2 = MediaPlayer.create(this, R.raw.dog_bark);
player2.setLooping(true);
player2.seekTo(0);
totalTime2 = player2.getDuration();
//SeekBar
seekBar1 = findViewById(R.id.seekbar1);
seekBar2 = findViewById(R.id.seekbar2);
seekBar1.setMax(totalTime1);
seekBar2.setMax(totalTime2);
seekBar1.setOnSeekBarChangeListener(new SeekBar.OnSeekBarChangeListener() {
@Override
public void onProgressChanged(SeekBar seekBar, int progress1, boolean fromUser1) {
if (fromUser1) {
player1.seekTo(progress1);
seekBar1.setProgress(progress1);
}
}
@Override
public void onStartTrackingTouch(SeekBar seekBar) {
}
@Override
public void onStopTrackingTouch(SeekBar seekBar) {
}
});
seekBar2.setOnSeekBarChangeListener(new SeekBar.OnSeekBarChangeListener() {
@Override
public void onProgressChanged(SeekBar seekBar, int progress2, boolean fromUser2) {
if (fromUser2) {
player2.seekTo(progress2);
seekBar2.setProgress(progress2);
}
}
@Override
public void onStartTrackingTouch(SeekBar seekBar) {
}
@Override
public void onStopTrackingTouch(SeekBar seekBar) {
}
});
// Thread (Update SeekBar & TimeLabel)
new Thread(() -> {
while (player1 != null) {
try {
Message msg = new Message();
msg.what = player1.getCurrentPosition();
handler1.sendMessage(msg);
Thread.sleep(1000000000);
} catch (InterruptedException e) {
}
}
}).start();
new Thread(() -> {
while (player2 != null) {
try {
Message msg = new Message();
msg.what = player2.getCurrentPosition();
handler2.sendMessage(msg);
Thread.sleep(1000000000);
} catch (InterruptedException e) {
}
}
}).start();
// Admob Banner Ad
MobileAds.initialize(this, initializationStatus -> {
});
AdView mAdView = findViewById(R.id.adView);
AdRequest adRequest = new AdRequest.Builder().build();
mAdView.loadAd(adRequest);
// Caution dialog
SharedPreferences preferences = getSharedPreferences("prefs", MODE_PRIVATE);
boolean firstStart = preferences.getBoolean("firstStart", true);
if (firstStart) {
showDialog();
}
}
// Caution dialog
private void showDialog() {
new AlertDialog.Builder(this)
.setTitle("Caution!")
.setMessage("In case you're wearing any kind of headphones please remove it before playing the ' Howl ' audio")
.setPositiveButton("ok", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
dialogInterface.dismiss();
}
})
.create().show();
SharedPreferences preferences = getSharedPreferences("prefs", MODE_PRIVATE);
SharedPreferences.Editor editor = preferences.edit();
editor.putBoolean("firstStart", false);
editor.apply();
}
private Handler handler1 = new Handler() {
@Override
public void handleMessage(@NonNull Message msg) {
int currentPosition1 = msg.what;
//Update SeekBar
seekBar1.setProgress(currentPosition1);
// Update Timelable
String elapsedTime1 = createTimerLable1(currentPosition1);
elapsedTimeLable1.setText(elapsedTime1);
String remainingTime1 = createTimerLable1(totalTime1 - currentPosition1);
remainingTimeLable1.setText("- " + remainingTime1);
}
};
private Handler handler2 = new Handler() {
@SuppressLint("SetTextI18n")
@Override
public void handleMessage(@NonNull Message msg) {
int currentPosition2 = msg.what;
// Update SeekBar
seekBar2.setProgress(currentPosition2);
// Update Timelable
String elapsedTime2 = createTimerLable2(currentPosition2);
elapsedTimeLable2.setText(elapsedTime2);
String remainingTime2 = createTimerLable2(totalTime2 - currentPosition2);
remainingTimeLable2.setText("- " + remainingTime2);
}
};
public String createTimerLable1(int duration) {
String timerLabel1 = "";
int min = duration / 1000 / 60;
int sec = duration / 1000 % 60;
timerLabel1 += min + ":";
if (sec < 10) timerLabel1 += "0";
timerLabel1 += sec;
return timerLabel1;
}
public String createTimerLable2(int duration) {
String timerLabel2 = "";
int min = duration / 1000 / 60;
int sec = duration / 1000 % 60;
timerLabel2 += min + ":";
if (sec < 10) timerLabel2 += "0";
timerLabel2 += sec;
return timerLabel2;
}
public void playBtnClick1(View view) {
if (player2.isPlaying()) {
player2.pause();
play2.setImageResource(R.drawable.ic_baseline_play_circle_filled_24);
}
if (!player1.isPlaying()) {
// Stoping
player1.start();
play1.setImageResource(R.drawable.ic_baseline_pause_circle_filled_24);
} else {
// Playing
player1.pause();
play1.setImageResource(R.drawable.ic_baseline_play_circle_filled_24);
}
}
public void playBtnClick2(View view) {
if (player1.isPlaying()) {
player1.pause();
play1.setImageResource(R.drawable.ic_baseline_play_circle_filled_24);
}
if (!player2.isPlaying()) {
// Stoping
player2.start();
play2.setImageResource(R.drawable.ic_baseline_pause_circle_filled_24);
} else {
// Playing
player2.pause();
play2.setImageResource(R.drawable.ic_baseline_play_circle_filled_24);
}
}
}
推薦答案
這么好，為什么線程應(yīng)該休眠1000000000毫秒。
在這種情況下，您的線程每隔1000000秒執(zhí)行一次任務(wù)。
1000000000毫秒=>；1000000秒=>；16666分鐘=>；277小時(shí)
所以您的線程每277小時(shí)執(zhí)行一次任務(wù)。
睡眠的參數(shù)是毫秒，所以把1000(1秒)或類似的東西放在更短的地方。
如果這不是解決方案，請(qǐng)讓我知道。
這篇關(guān)于媒體播放器-搜索欄和時(shí)間標(biāo)簽沒有進(jìn)展的文章就介紹到這了，希望我們推薦的答案對(duì)大家有所幫助，
