為了說(shuō)明這一點(diǎn)，我們創(chuàng)建以下視圖 –
mysql> CREATE VIEW digits AS
-> SELECT 0 AS digit UNION ALL
-> SELECT 1 UNION ALL
-> SELECT 2 UNION ALL
-> SELECT 3 UNION ALL
-> SELECT 4 UNION ALL
-> SELECT 5 UNION ALL
-> SELECT 6 UNION ALL
-> SELECT 7 UNION ALL
-> SELECT 8 UNION ALL
-> SELECT 9;
Query OK, 0 rows affected (0.08 sec)
mysql> CREATE VIEW numbers AS SELECT ones.digit + tens.digit * 10 + hundreds.digit * 100 + thousands.digit * 1000 AS number FROM digits as ones, digits as tens, digits as hundreds, digits as thousands;
Query OK, 0 rows affected (0.09 sec)
mysql> CREATE VIEW dates1 AS SELECT SUBDATE(CURRENT_DATE(), number) AS date FROM numbers UNION ALL SELECT ADDDATE(CURRENT_DATE(), number + 1) AS date FROM numbers;
Query OK, 0 rows affected (0.09 sec)
mysql> Select date from dates1 where date between '2017-11-15' and '2017-11-30'order by date;
+------------+
| date |
+------------+
| 2017-11-15 |
| 2017-11-16 |
| 2017-11-17 |
| 2017-11-18 |
| 2017-11-19 |
| 2017-11-20 |
| 2017-11-21 |
| 2017-11-22 |
| 2017-11-23 |
| 2017-11-24 |
| 2017-11-25 |
| 2017-11-26 |
| 2017-11-27 |
| 2017-11-28 |
| 2017-11-29 |
| 2017-11-30 |
+------------+
16 rows in set (0.05 sec)
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以上就是如何借助 MySQL 視圖從日期范圍生成天數(shù)？的詳細(xì)內(nèi)容，更多請(qǐng)關(guān)注www.92cms.cn其它相關(guān)文章！
